Bar Graphs — PYPs

8 solved Bar Graphs previous year questions (PYQs) from past year papers — attempt each and check the answer.

Q1:ipmat indore 2019LRDI › Bar GraphsEasyMCQ · MCQ

Analyze the given data for exports and imports of rubber in Rs. crores from 2006 to 2017 and answer the questions based on the analysis.

Average annual exports for the given period 2006-2017 was approximately

• ARs. 230 Cr
• BRs. 220 Cr
• CRs. 210 Cr
• DRs. 190 Cr

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$\text{Average} = \dfrac{\text{Sum of annual exports across all years}}{\text{Number of years}}$ $=\dfrac{280+280+230+210+200+220+210+200+200+200+220+200}{12}$ $=\dfrac{2650}{12}\approx220$ crores. Final Answer: Rs. 220 Cr

Q2:ipmat indore 2019LRDI › Bar GraphsEasyMCQ · MCQ

Analyze the given data for exports and imports of rubber in Rs. crores from 2006 to 2017 and answer the questions based on the analysis.

The percentage decline in exports during the period 2006-2011 is more than the percentage decline in exports during 2012-2017 by approximately

• A16.5
• B20.5
• C12.5
• D21.5

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Percentage decline during 2006-2011 period $=\frac{\text{Difference between 2006 and 2011 exports}}{\text{2006 exports}}\times100$ $=\frac{280-220}{280}\times100=\frac{60}{280}\times100=\text{approximately }21.42$% Now, percentage decline during 2012-2017 period will be calculated similarly. $=\frac{210-200}{210}\times100=\frac{10}{210}\times100=\text{approximately } 4.76$% As we can see, the first percentage is more than the second by approximately $16.5$, hence Option 1 is the answer. Final Answer: 16.5

Q3:ipmat indore 2019LRDI › Bar GraphsEasyMCQ · MCQ

Analyze the given data for exports and imports of rubber in Rs. crores from 2006 to 2017 and answer the questions based on the analysis.

The maximum difference between imports and exports is

• ARs. 60 Cr
• BRs. 110 Cr
• CRs. 120 Cr
• DRs. 100 Cr

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The phrase *difference between imports and exports* means the gap within a single year - the two bars standing side by side - so we compare year by year rather than picking the tallest bar from one year and the shortest from another. Reading the pairs off the chart and measuring the size of the gap between the two bars. Note that in 2006 and 2007 exports were the higher of the two, so the gap runs the other way in those years - what matters is how far apart the bars stand, not which is on top:

Year	Imports	Exports	Gap
2006	220	280	60
2007	240	280	40
2008	260	230	30
2009	280	210	70
2010	310	200	110
2011	290	220	70
2012	320	210	110
2013	300	200	100
2014	320	200	120
2015	310	200	110
2016	250	220	30
2017	240	200	40

The largest gap is in 2014, where imports peak at Rs. 320 Cr while exports sit at their floor of Rs. 200 Cr: $$320 - 200 = \text{Rs. }120\text{ Cr}$$ A shortcut is tempting here - take the tallest import bar anywhere (320, in 2012 and 2014) and subtract the shortest export bar anywhere (200, in 2010, 2013, 2014, 2015 and 2017). It gives the right number only because 2014 happens to hold both extremes at once. On a chart where the highest import and the lowest export fell in different years, that shortcut would compare two bars that never coexist and overstate the answer. Scanning the pairs is the reliable route. Final Answer: Rs. 120 Cr

Q4:ipmat indore 2019LRDI › Bar GraphsEasyMCQ · MCQ

Analyze the given data for exports and imports of rubber in Rs. crores from 2006 to 2017 and answer the questions based on the analysis.

Balance of trade is defined as imports subtracted from exports ( = exports - imports). Which of the following blocks of three years has witnessed the largest average negative balance of trade?

• A2007-2009
• B2015-2017
• C2014-2016
• D2010-2012

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For 2007-2009: 2007: $280 - 240 = 40$ 2008: $230 - 260 = -30$ 2009: $210 - 280 = -70$ Average = $\frac{40 - 30 - 70}{3} = -20$ For 2015-2017: 2015: $200 - 310 = -110$ 2016: $220 - 250 = -30$ 2017: $200 - 240 = -40$ Average = $\frac{-110 - 30 - 40}{3} = -60$ For 2014-2016: 2014: $200 - 320 = -120$ 2015: $200 - 310 = -110$ 2016: $220 - 250 = -30$ Average = $\frac{-120 - 110 - 30}{3} = -86.67$ For 2010-2012: 2010: $200 - 310 = -110$ 2011: $220 - 290 = -70$ 2012: $210 - 320 = -110$ Average = $\frac{-110 - 70 - 110}{3} = -96.67$ After comparing, the period 2010-2012 has the largest negative average balance of trade at $-96.67$ crores, making it the correct answer. Final Answer: 2010-2012

Q5:jipmat 2025LRDI › Bar GraphsMediumLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam: The average number of students who qualified in the examination from Kolkata and Delhi is what percent of the average number of students who appeared for the exam from the same cities? (rounded off to 2 digits after the decimal)

• A58.61
• B62.58
• C73.91
• D77.96

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Read the two cities off the chart: Kolkata had $3250$ appear and $2250$ qualify; Delhi had $2500$ appear and $2000$ qualify. Average qualified $=\frac{2250+2000}{2}=\frac{4250}{2}=2125$. Average appeared $=\frac{3250+2500}{2}=\frac{5750}{2}=2875$. 'A is what percent of B' means $\frac{A}{B}\times100$, so the answer is $\frac{2125}{2875}\times100=73.9130\ldots$ The third decimal digit is $3$, so rounding to two places gives 73.91% - Option 3.

Q6:ipmat indore 2019LRDI › Bar GraphsEasyMCQ · MCQ

Analyze the given data for exports and imports of rubber in Rs. crores from 2006 to 2017 and answer the questions based on the analysis.

The percentage increase in imports over the previous year is maximum during

• A2009 to 2010
• B2010 to 2011
• C2013 to 2014
• D2008 to 2009

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The percentage increase in imports for each given option using the formula: $\frac{\text{New Value - Original Value}}{\text{Original Value}} \times 100$ 2009 to 2010: Imports 2009: $280$ Imports 2010: $310$ Percentage increase = $\frac{310 - 280}{280} \times 100 = \frac{30}{280} \times 100 = 10.71\%$ 2010 to 2011: Imports 2010: $310$ Imports 2011: $290$ This is a decrease: $\frac{290 - 310}{310} \times 100 = -6.45\%$ 2013 to 2014: Imports 2013: $300$ Imports 2014: $320$ Percentage increase = $\frac{320 - 300}{300} \times 100 = \frac{20}{300} \times 100 = 6.67\%$ 2008 to 2009: Imports 2008: $260$ Imports 2009: $280$ Percentage increase = $\frac{280 - 260}{260} \times 100 = \frac{20}{260} \times 100 = 7.69\%$ Comparing all values, the maximum percentage increase was $10.71\%$ during 2009 to 2010, making this the correct answer. Final Answer: 2009 to 2010

Q7:jipmat 2025LRDI › Bar GraphsMediumLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam: What is the difference between the average number of students who appeared in the entrance exam from all the given cities and the average number of students who qualified from all the cities together?

• A950
• B990
• C1100
• D1020

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Both averages are over the same five cities, so read each series off the chart and divide by $5$. Appeared: $\frac{3000+2250+3250+2500+3000}{5}=\frac{14000}{5}=2800$. Qualified: $\frac{1750+1250+2250+2000+2000}{5}=\frac{9250}{5}=1850$. Difference $=2800-1850=**950**$ - Option 1. Shortcut: since both are divided by the same $5$, you can subtract the totals first - $\frac{14000-9250}{5}=\frac{4750}{5}=950$.

Q8:jipmat 2025LRDI › Bar GraphsEasyLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam: The number of students who appeared for the exam from Delhi is approximately what percent of the total number of students who appeared for the exam from all the cities together?

• A24%
• B18%
• C28%
• D12%

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From the chart, $2500$ students appeared from Delhi. Across all five cities, $3000+2250+3250+2500+3000=14000$ appeared. Required percentage $=\frac{2500}{14000}\times100=17.857\ldots\%$, which is approximately 18% - Option 2. The other options are far off: $24\%$ would need about $3360$ students and $12\%$ only $1680$.

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