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Binomial Theorem — PYPs

2 solved Binomial Theorem previous year questions (PYQs) from past year papers — attempt each and check the answer.

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Q1:ipmat indore 2023QABinomial TheoremMediumSA · TITA
If three consecutive coefficients in the expansion of (x+y)n(x+y)^n are in the ratio 1:9:631:9:63, then the value of nn is
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The Setup: We are given three consecutive coefficients in the binomial expansion of (x+y)n(x+y)^n strictly in the ratio 1:9:631:9:63. We must determine the power nn. Step 1: Express the coefficients algebraically. Let the three consecutive coefficients be (nr1)\binom{n}{r-1}, (nr)\binom{n}{r}, and (nr+1)\binom{n}{r+1}. We are given two ratio equations: (nr)(nr1)=91=9\frac{\binom{n}{r}}{\binom{n}{r-1}} = \frac{9}{1} = 9 (nr+1)(nr)=639=7\frac{\binom{n}{r+1}}{\binom{n}{r}} = \frac{63}{9} = 7 Step 2: Apply the standard binomial coefficient ratio formula. The ratio (nk)(nk1)\frac{\binom{n}{k}}{\binom{n}{k-1}} simplifies universally to nk+1k\frac{n - k + 1}{k}. Apply this to our first equation (k=rk = r): nr+1r=9    nr+1=9r    n=10r1\frac{n - r + 1}{r} = 9 \implies n - r + 1 = 9r \implies n = 10r - 1 Apply this to our second equation (k=r+1k = r + 1): n(r+1)+1r+1=7    nrr+1=7    nr=7r+7    n=8r+7\frac{n - (r+1) + 1}{r+1} = 7 \implies \frac{n - r}{r + 1} = 7 \implies n - r = 7r + 7 \implies n = 8r + 7 Step 3: Solve the linear system for rr and nn. Equate the two expressions for nn: 10r1=8r+710r - 1 = 8r + 7 2r=8    r=42r = 8 \implies r = 4 Substitute rr back into either equation to find nn: n=10(4)1=39n = 10(4) - 1 = 39 Final Answer: 39
Q2:ipmat indore 2022QABinomial TheoremEasySA · TITA
The sum of the coefficients of all the terms in the expansion of (5x9)4(5 x-9)^{4} is __________.
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The Setup: We are asked to find the arithmetic sum of the coefficients of all terms within the binomial expansion of (5x9)4(5x-9)^4. Step 1: Apply the polynomial coefficient property. For any polynomial P(x)P(x), the sum of its fully expanded coefficients is mathematically obtained by evaluating the polynomial at x=1x = 1. Step 2: Evaluate the expression at x=1x = 1. P(1)=(5(1)9)4P(1) = (5(1) - 9)^4 P(1)=(59)4P(1) = (5 - 9)^4 P(1)=(4)4P(1) = (-4)^4 P(1)=256P(1) = 256 Final Answer: 256

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